An object of mao 5 kg is acted upon by a force
of 10N starting from rest
how much is distance
covered by the object in 10 sec?
Answers
Answer :
The distance covered by object is 100m
Step-by-step Explanation :
Given : mass of an object = 5kg
Force applied on it = 10N
Initial velocity (u) = 0
Time of motion (t) = 10 sec
To find: Distance covered in 10 sec = ?
We know that,
Force = Mass × Acceleration
Substituting the given value in above formula
We get,
10 = 5 × Acceleration
Acceleration (a) = 10 / 5 = 2 m/s²
Also,
s = ut + 1/2 at²
Where,
s = distance covered by object
Substituting the value in above formula,
We get,.
s = 0 × 10 + 1/2 × 2 × (10)²
s = 1/2 × 2 × 100
s = 100 m
Therefore the distance covered by object is 100m