Question

An object of mass 0.16kg is moving forwards at a speed of 0.50m/s.
A second object of mass 0.10kg is at rest.
The first object strikes the second object.
After the collision, the second object moves forwards at a speed of 0.50m/ s.
What is the speed of the first object after the collision?

(solution please:)
A 0.0m/s
B 0.19m/ s
C 0.31m/s
D 0.50m/s

Answer 1

Answer:

SoluTion :-

Momentum before collision = Momentum after collision

\sf {m_{1}u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}}m

1

u

1

+m

2

u

2

=m

1

v

1

+m

2

v

2

\sf {(0.16 kg) (0.50 m/s) + (0.10 kg) (0 m/s) = (0.16 kg) v_{1} + (0.10 kg) (0.50 m/s)}(0.16kg)(0.50m/s)+(0.10kg)(0m/s)=(0.16kg)v

1

+(0.10kg)(0.50m/s)

\sf {0.08\ kg\ m/s = (0.16 kg) v_{1} + 0.05\ kg\ m/s}0.08 kg m/s=(0.16kg)v

1

+0.05 kg m/s

\sf {0.03\ kg\ m/s = (0.16\ kg) v_{1}}0.03 kg m/s=(0.16 kg)v

1

\sf {v_{1} = 0.19 m/s}v

1

=0.19m/s

Answer 2

Answer:

option B is the nearest answer of this question