Question

An object of mass 0.25 kg is moved from rest by a force of 20 N. When does it gain 80m/s
speed while moving along a straight line. Also calcuate the distance covered during that time.

Answer 1

HIII......

THERE IS YOUR ANSWER....

[tex]mass = 0.25kg \\ force = 20 \\ force = mass \times acceleration(a) \\ 20 = 0.25 \times acceleration \\ acceleration = 80 \frac{m}{ {sec}^{2} } \\ as \: body \: starts \: from \: rest \\ final \: velocity \: (v) \: = 80 \\ \\ v = a \times time \\ 80 = 80 \times time \\ time = 1sec

v^2=2as

6400=2*80*s

s=40m

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