an object of mass 0.2kg is moving in a circular orbit of radius 1 m with the speed of 5m/s therefore,the centripetal force acting on the object is ____N
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Answered by
4
Step-by-step explanation:
the answer is 5N
using the formula,F=mv^2
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r
!!!
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Answered by
3
Centripetal force = mv²/r
Given that:-
m = 0.2 kg
v = 5 m/s
r = 1 m
C.F. = mv²/r = (0.2)25/1 = 5 N
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