Question

An object of mass 0.80 kg is moving in a straight line at a velocity of 2.0 m/s. A force is exerted on the object, in the direction of motion, for a period of 1.0 minute and the velocity of the object increases to 6.0 m/s.

What force is exerted on the object?​

Answer 1

Answer:

0.0533N

Explanation:

Let, the exerted force on object is F

Let, v = Final value of speed, u = Initial value of speed, t = time , a = acceleration = \frac{F}{m}

m

F

, m = mass of the object

According to the formula,

v = u + at

=> a = \frac{v - u}{t}

t

v−u

=> \frac{F}{m}

m

F

= \frac{v - u}{t}

t

v−u

=> F = m*\frac{v - u}{t}

t

v−u

=> F = 0.8 * \frac{6 - 2}{60}

60

6−2

[ time (t) = 1 min = 60 sec]

=> F = \frac{4}{75}

75

4

= 0.0533 N