Question

An object of mass 0.9 kg is attached to a massless string of length 3 m, and swung with a tangential velocity of 3 m/s. What is the force exerted by the string on the object?

Answer 1

$2.7 N$

Explanation:

$Given, \: \: \: m = 0.9 \: kg, \: r = 3 \: m \\ \: \: \: \: \: \: \: \: \: \: \: and \: \: \: v = 3 \: m {s}^{ - 1} \\ we \: \: know \: \: \boxed{force \:(F) = \frac{m {v}^{2} }{r} } \\ Now, \: \: putting \: \: values \\ force = \frac{0.9 \: kg \times (3 \: m {s}^{ - 1} )^{2} }{3 \: m} \\ = \frac{0.9 \times 9}{3} N \\ = \boxed{2.7N}$