Question

An object of mass 1.2 kg is moving with a velocity of 2.0 m / s when it is acted on by a force of 4.0N. The velocity of the object increases to 5.0m / s. For what period of time does the force act on the object? A=0.90s B=1.1s C=1.5s D=3.6s

Answer 1

Answer:

An object of mass 1.2 kg is moving with a velocity of 2.0 m / s when it is acted on by a force of 4.0N. The velocity of the object increases ...

Explanation:

Answer 2

Answer:

A).0.90s

Explanation:

Given,

Mass of object= 1.2 kg

initial velocity(u) of the object=2.0 m/sec

final velocity (v) of the object(after increasing)=5.0 m/sec

Force= 4.0 N.

we have to find period of time at which force is acted on the object

calculation:

we know when an object moving with initial velocity u and with acceleration a in period of time t.Then final velocity is given by equation

 $v=u+at$

$therefore \\a=\frac{v-u}{t}$

Force exerted by object is given by

$F=m*a$$=m(\frac{v-u}{t} )$

         $4=(1.2)\frac{(5-2)}{t} \\\\t=0.9sec$                

period of time at which force is acted on the object is 0.90 sec

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