An object of mass 1 kg is made to slide down a smooth inclined plane of length 20m. If the kinetic
energy possessed by the body at the bottom of the plane is 100 J, then the inclination of the plane
with the horizontal is : (take g = 10 ms-2)
(A) 45°
(B) 37°
(C) 60°
(D) 30°
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Answered by
4
Answer:
Gain in kinetic energy = potential energy so
U=mgh sintheta
100=1*10*20*sin theta
1/2= sin theta
Theta =30
Here sintheta is due to vertical component of h
Answered by
1
Answer:
answer d is correct 30 degree
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