Question

An object of mass 1 kg moves with an initial velocity of 20 metre per second how much is the force in Newton required to change the velocity to 30 metre per second in one millisecond

Answer 1

Answer:

here is your answer hope it help

Answer 2

Answer:

• The Force (F) on the object is 10⁴ N

Given:

1. Mass of the body (M) = 1 Kg
2. Initial velocity (u) = 20 m/s
3. Final velocity (v) = 30 m/s
4. Time (t) = 1 millisecond =  10⁻³ sec

Explanation:

$\rule{300}{1.5}$

From the formula we know,

$\displaystyle \bigstar\;\boxed{\sf F=M\;a}$

Here,

• F Denotes Force.

• M Denotes Mass.

• a Denotes Acceleration.

Now,

$\displaystyle\dashrightarrow\sf F=M\;a\\\\\\\dashrightarrow\sf F=M\;\Bigg(\dfrac{v-u}{t}\Bigg)\\\\\\\dag\; \bf{Substituting\;the\;values}\\\\\\\dashrightarrow\sf F=1\;Kg\times\Bigg(\dfrac{30-20}{10^{\;-3}}\Bigg)\\\\\\\dashrightarrow\sf F=1\times\Bigg(\dfrac{30-20}{10^{\; -3}}\Bigg)\\\\\\\dashrightarrow\sf F=1\times\Bigg(\dfrac{10}{10^{\; -3}}\Bigg)\\\\\\\dashrightarrow\sf F=1\times\Bigg(\dfrac{10\times10^{\;3}}{1}\Bigg)\\\\\\\dashrightarrow\sf F=1\times 10^{\;(3+1)}$

$\displaystyle \dashrightarrow\sf F=1\times 10^{\;4}\\\\\\\dashrightarrow\sf F=10^{\;4}\\\\\\\dashrightarrow \large{\underline{\boxed{\red{\sf F=10^{\;4}\;N}}}}$

∴ The Force (F) on the object is 10⁴ N.

$\rule{300}{1.5}$