Question

an object of mass 1 kg travelling in a straight line with a velocity of 10 metre per second collides with and stick to a stationary wooden block of mass 5 kg then they both move off together in the same straight line. calculate the total Momentum just before the impact and just after impact. also calculate the velocity of the combined object


Please help ​

Answer 1

Given,

Mass of object, m1 = 1kg

Velocity of object, v1 = 10m/s

$\therefore \: momentum \: of \: object \: = \: m1 \times v1$

$= 1 \times 10 \: kg \: m {s}^{ - 1}$

$= 10 \: kg \: m {s}^{ - 1}$

Now,

Mass of wooden block, m2 = 5 kg

Velocity of wooden block, v2 = 0

$\therefore \: momentum \: of \: wooden \: block \: = \: m2 \times \: v2$

$= 5 \times 0$

$= 0 \: kg \: m {s}^{ - 1}$

$So, \\ the \: total \: Momentum \: before \: impact \: = \: 10 + 0$

$= 0 \: kg \: m {s}^{ - 1}$

According to the law of conservation of momentum, the total just after the impact will be the same as the total Momentum just before the impact. This means momentum = 10 kg m/s

Now,

Total Momentum = 10 kg m/s

Total mass of object and wooden block

= 1 kg + 5 kg

= 6 kg

And the velocity of object and wooden block

= v m/s

$\longrightarrow \: 10 = 6 \times v$

$\longrightarrow \: v \: = \frac{ \cancel{10}} {\cancel{6} }$

$\longrightarrow \: v \: = \: 1.67 \: m {s}^{ - 1}$

Answer 2

Answer:

9.5

Explanation:10*9.5