Question

An object of mass 1 kg travelling in a straight line with a velocity of 10 m s−1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Answer 1

Answer:

total momentum before collision=total momentum after collision.

( m1 x v1 ) + ( m2 x v2) = V(m1+m2)

so before collision: ( m1 x v1 ) + ( m2 x v2 )

1x10=10kjm/s

Explanation:

Answer 2

Answer:

according to the principle of conservation of linear momentum,momentum will always remain constant before and after collision.

so;(m1×v1)=momentum  before and after collision

1kg×10m/s=10kgm/s

then for the speed after impact;

momentum=(m1+m2)v,where v is the common velocity

10kgm/s=(1kg+5kg)v

10=6v

10/6=6v/6

v=6.67m/s

the velocity of the combined bodies =6.67,m/s

Explanation: