Question

An object of mass 1 kg travelling in a straight line with a velocity of collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Answer 1

Answer:

given,

Explanation:

m=1kg

ANSWER

Given : m

1

=1kg m

2

=5kg u

1

=10 ms

−1

u

2

=0

Momentum of the system just before collision, P

i

=m

1

u

1

+m

2

u

2

P

i

=1×10+5×0=10 kgms

−1

Mass of the combined object, M=m

1

+m

2

=6kg

Let velocity of combined object be v

According to conservation of momentum, momentum of the system just after the collision, P

f

=P

i

⟹P

f

=10 kg m s

−1

Mv=10

or, 6×v=10

or, v=1.67 m/s

10kg

Answer 2

Answer:

Given

An object of mass 1 kg travelling in a straight line with a velocity

of 10 m s' collides with, and sticks to, a stationary wooden

block of mass 5 kg. Then they both move off together in the

same straight line

To Find

Total momentum before impact

Total momentum after impact

Velocity of combined object

Solution

Let the two object be object a and object b

⟹ Momentum (a) = m × v

⟹ Momentum (a) = 1 × 10

⟹ momentum (a) = 10 kgm/s

Now

Since velocity of object b is 0 So, The momentum will be 0

⟹ Total Momentum = 10 kgm/s

Now

⟹ Momentum after it collides = m × v

⟹ Momentum after collides = 6 × v

⟹ Momentum after collides = 6v

Now

Since mass remain same. So,

Momentum before collision = Momentum after collision

⟹ 10 = 6v

⟹ 10/6 = v

⟹ 1.66 = v

Explanation:

Hope it helps you