Question

An object of mass 1 kg travelling in a straight line with a velocity of 10 m/s collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Explanation:

Given-

m1= 1kg

u1= 10 m/s

m2= 5 kg

u2= 0m/s

v= ?

As the 2 objects stuck together their velocity will be the same.

According to the law of conservation of momentum,

m1u1 + m2u2= m1v1 + m2u2

Therefore,

1×10 + 5×0= (5+1)v

10+0= 6v

∴ Total momentum before collusion = 10 kg m/s

v = 10/6

∴ v= 1.67 m/s