Question

An object of mass 1 kg travelling in a straight
line with a velocity of 10 m s-1 collides with,
and sticks to, a stationary wooden block of
mass 5 kg. Then they both move off together
in the same straight line. Calculate the total
momentum just before the impact and just
after the impact. Also, calculate the velocity of
the combined object.​

Answer 1

Answer:

Here is your Answer!!

Explanation:

Given

m = 1kg,

u1=10ms−1

M=5 kg and

u2= 0ms−1

Find out

The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Solution

From conservation of momentum

Initial momentum = final momentum

mu1 + Mu2 = (m+M)v

1×10 + 5×0 = (1+5)v

10=6v

Hence, the velocity of both is v =5/3ms−1

Total momentum before is 10 kgms−1

From momentum conservation, total momentum after is 10kgms−1.

Answer 2

Answer:

m = 1kg,

u1=10ms−1

M=5 kg and

u2= 0ms−1

The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Solution

From conservation of momentum

Initial momentum = final momentum

mu1 + Mu2 = (m+M)v

1×10 + 5×0 = (1+5)v

10=6v

Hence, the velocity of both is v =5/3ms−1

Total momentum before is 10 kgms−1

From momentum conservation, total momentum after is 10kgms−1