Question

An object of mass 1 kg travelling in a straight line with a velocity of 10 m/s collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.​

Answer 1

Explanation:

Given

m = 1kg,

u1=10ms−1

M=5 kg and

u2= 0ms−1

Find out

The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Solution

From conservation of momentum

Initial momentum = final momentum

mu1 + Mu2 = (m+M)v

1×10 + 5×0 = (1+5)v

10=6v

Hence, the velocity of both is v =5/3ms−1

Total momentum before is 10 kgms−1

From momentum conservation, total momentum after is 10kgms−1.

Answer 2

★Answer★

Given

m = 1kg,

u1=10ms−1

M=5 kg and

u2= 0ms−1

Find out

The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Solution

From conservation of momentum

Initial momentum = final momentum

mu1 + Mu2 = m+Mv

1×10 + 5×0 = 1+5v

10=6v

Hence, the velocity of both is v =5/3ms−1

Total momentum before is 10 kgms−1

From momentum conservation, total momentum after is 10kgms−1.

I hope it helps you ✌️✌️