Question

an object of mass 1 kilogram is released from the top of a tower of height 125 meters what time will it take to strike the ground​

Answer 1

Answer:

5 s

Explanation:

Given:

• Mass (m) = 1 kg
• Initial velocity (u) = 0 m/s
• Height (h) = 125 m

To find:

• Time taken (t) = ?

Solution:

As we remember, Newton's 2nd equation of motion i.e, s = ut + ½ × at².

Here, we know all the values where 'a' is acceleration whose value we takes 10 metre/second², 's' is distance or height, 'up is the initial velocity of object except time. Just substitute all the values.

(However, there's no need of mass)

⇒ 125 = 0 × t + 1/2 × 10 × t²

⇒ 125 = 0 + 5t²

⇒ 125/5 = t²

⇒ 25 = t²

⇒ $\sf{\sqrt{25}\:=\:t}$

⇒ 5 = t

Therfore, time taken to strike the ground is 5 seconds.

Answer 2

Given:-

• Mass (m) = 1 kg
• Initial velocity (u) = 0 m/s
• Height (h) = 125 m

⠀

To find:-

• Time taken (t) to strike the ground.

⠀

Solution:-

☆ In this question we have given the mass of an object, initial velocity of an object and height of an object. We have to find out the time taken to strike the ground. Let's do it.

⠀

According to the question,

⠀

⇢ 125 = 0 × t + 1/2 × 10 × t²

⇢ 125 = 0 + 5t²

⇢ 125/5 = t²

⇢ 25 = t²

⇢ √25 = t

⇢ t = 5

⠀

Hence,

• Time taken to strike the ground in 5 seconds.