Question

An object of mass 1 kilogram is released from the top of a tower of height 125 meters what time will it take to strike the ground​
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Answer 1

Answer:

• $5\:s$

Explanation:

$Given:-$

• Mass = 1 kg

• Initial velocity = 0 m/s

• Height = 125 m

$ToFind:-$

• Time taken

$Solution :-$

$Using \ 2nd \ equation \ of \ motion$

$\implies \:\:s = ut + \frac{1}{2} \times at^2$

$\implies \:\: 125 = 0 \times t + \frac{1}{2}\times 10 \times t^2$

$\implies \:\: 125 = 0 + 5t^2$

$\implies \:\: 25 = t^2$

$\implies \:\: \sqrt{25}\:=\:t$

$\implies \:\: 5 = t$

Object takes 5 seconds to strikes the ground

Answer 2

Answer:

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Explanation:

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