Question

An object of mass 10 gram is sliding with a constant velocity of 2 metre per second on a frictionless horizontal table. The force required to keep the object moving with the same velocity is?

Answer 1

Given:

An object of mass 10 gram is sliding with a constant velocity of 2 metre per second on a frictionless horizontal table.

To find:

Force required to keep the object moving with same Velocity

Calculation:

Force is a vector quantity responsible for changing the Velocity of the body in linear motion.

$\therefore \rm{force = mass \times acceleration}$

$= > \rm{force = m \times a}$

$= > \rm{force = ( \dfrac{10}{1000}) \times ( \dfrac{v - u}{t} )}$

$= > \rm{force = {10}^{ - 2} \times ( \dfrac{v - u}{t} )}$

$= > \rm{force = {10}^{ - 2} \times ( \dfrac{2 - 2}{t} )}$

$= > \rm{force = {10}^{ - 2} \times ( \dfrac{0}{t} )}$

$= > \rm{force = {10}^{ - 2} \times 0}$

$\boxed{ = > \rm{force = 0 \: N}}$

So, no force is required to maintain the Velocity of the body.

Answer 2

Hey There!

Given:

• Mass = 10gm

• Acceleration = 2m/s²

To Find:

• Force = ?

Solution:

We know Formula for Force,

$✓ \: </strong><strong>F</strong><strong> = ma$

Substituting Values as per Conditions,

$⟶f = ( \frac{10}{1000} ) \times \frac{v - u}{t}$

$⟶f = \frac{\cancel{10}}{\cancel{1000}} \times \frac{v - u}{t}$

$⟶f = {10}^{ - 2} \times ( \frac{2 - 2}{t} )$

$⟶f = {10}^{ - 2} = \frac{0}{t}$

$⟶f = {10}^{ - 2} \times 0$

$⟶f = 0N$

⛬ There is no force required to keep object moving along with same Velocity.