Question

An object of mass 10 kg is moving with a velocity of 20m/s.A force is applied so that in 20sec it attains a velocity of 30m/s what is the force applied on the object?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force\:applied=5\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: object(m) = 10 \: kg \\ \\ \tt: \implies Initial \: velocity(u) = 20 \: m/s \\ \\ \tt: \implies Final \: velocity(v) = 30 \: m/s \\ \\ \tt: \implies Time(t) = 20 \: sec \\ \\ \red{\underline \bold{To \:Find :}} \\ \tt: \implies Force \: applied(F) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 30 = 20 + a \times 20 \\ \\ \tt: \implies 30 - 20 =20 \times a \\ \\ \tt: \implies a = \frac{10}{20} \\ \\ \green{\tt: \implies a = 0.5 \: ms^{2} } \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies F= ma \\ \\ \tt: \implies F= 10 \times 0.5 \\ \\ \green{\tt: \implies F = 5 \: N} \\ \\ \green{\tt \therefore Force \: applied \: is \: 5 \: N}$