Question

An object of mass 10 kg moves at a constant speed of 10 m/s. A constant force, that acts for 4 s on the
object, gives it a speed 2 m/s in opposite direciton. The force acting on the object is -
(A)
-3N
(B)
-30 N
(C)
3N
(D)
30 N​

Answer 1

Vf= -2m/s

Vi= 10m/s

accleration= Vf-Vi/t

-2-10/4

-3m/s²

F= ma= 10*-3m/s²= -30N  B IS RIGHT ANSWER

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