Question

An object of mass 10 kg moves at a constant speed of
10ms ! A constant force that acts for 4 sec on the
object gives it a speed of 2ms-' in opposite direction.
The force acting on the object is​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force=3\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: body(m) = 10 \: kg \\ \\ \tt: \implies Initial \: speed(u) = 10 \: m/s \\ \\ \tt: \implies Final \: speed(v) = 2 \: m/s \\ \\ \tt: \implies Time (t) = 4 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Force \: Applied(F) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 2 = 10 + a \times 4\\ \\ \tt: \implies 2 - 10 = 10 \times a \\ \\ \tt: \implies a = \frac{-8}{4} \\ \\ \tt: \implies a =- 2{ \: m/s}^{2} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies F = ma \\ \\ \tt: \implies F = 10 \times -2 \\ \\ \green{\tt: \implies F= -20\: N} \\ \\ \green{\tt \therefore Force \: applied \: on \: object \: is \:20 \: N\:in\:opposite\:direction}$