Question

An object of mass 10 kg moving with a
speed of 15 m s' hits the wall and comes
to rest within
a) 0.03 second
b) 10 seconds
Calculate the impulse and average force
acting on the object in both the cases.​

Answer 1

Answer:

f=ma

f=m×(v-u/t)

f=10kg×(0-15/0.03)

f

Answer 2

Answer:

average forces acting on the both cases is 500N and 15N

Explanation:

Initial momentum of the object pi=10×15=150kg ms−1.

Final momentum of the object pf=0

Δp=150−0=150kgms−1

(a) Impulse j=Δp=150Ns

(b) Impulse j=Δp=150Ns

Average force Forg=ΔpΔt=1500.03=5000N

(b) Average force Forg=15010=15N

We see that, impulse is the same in both cases, but the average force is different.

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