an object of mass 10 kg tends to slide on an rough inclined plane of 30°. How much force is to be applied in upward direction along the inclined plane on the object so that it will tend to move up
Answers
Answer:
An object of mass 10 kg is to be kept at rest on an inclined plane making an angle of 370 to the horizontal by applying a force F along the ... If the block has tendency to slide down, friction on block will act upwards.
Answer:
mgsin37
0
=10×10×3/5=60N
f
l
=μ=0.2mgcos37
0
=0.2×10×10×4/5
=16N
Friction force alone is unable to balance mgsin37
0
. Hence, F is required for balancing. Here two cases arise.
Case I:
If the block has tendency to slide down, friction on block will act upwards.
F + 16 = 60
RightarrowF=44N
This is the minimum force required for balancing.
Case II: If the block has on tendency to slide up, friction on block will act downwards.
F = 60 + 16⇒ F= 76 N
This is the maximum force required for balancing.
Therefore, for balancing 44N≤F≤16N