An object of mass 10 kg travelling in a straight line with a velocity of 50 m s–1 collides with, and sticks to, a stationary wooden block of mass 15 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object
Answers
Explanation:
The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Solution
From conservation of momentum
Initial momentum = final momentum
mu1 + Mu2 = (m+M)v
1×10 + 5×0 = (1+5)v
10=6v
Hence, the velocity of both is v =5/3ms−1
Total momentum before is 10 kgms−1
From momentum conservation, total momentum after is 10kgms−1.
Answer:
- An object of mass 10 kg travelling in a straight line with a velocity of 50 m s–1 collides with, and sticks to, a stationary wooden block of mass 15 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Given
m = 1kg,
U₁=10ms 1
M=5 kg and
Find out
The total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.
Solution
From conservation of momentum
Initial momentum = final momentum
mu₁ + Mu₂ = (m+M)v
1x10 + 5x0 = (1+5)v
10=6v
Hence, the velocity of both is v = 5/3ms-¹
Total momentum before is 10 kgms¹
From momentum conservation, total momentum after is 10kgms ¹.
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