Question

An object of mass 100 kg accelerates uniformly at velocity of 5 M/s To 8 m/s in 6 seconds. Calculate the initial momentum and the final momentum of the object. Also find the force exerted on the object.

Answer 1

$\boxed{\boxed{\boxed{\purple{Hello \:Dear\:Students}}}}$

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✴The Mass of the object (m) = 100 kg

✴ Initial Velocity of the object (u) = 5 m/s

✴ Final Velocity of the object (v) = 8m/s

✴ The time taken (t) = 6 sec

$\boxed{Initial\:Momentum:}$

P = MU
P = 100 × 5
p = 500 kg m/s

$\boxed{Final\:Momentum:}$

P = MV
P = 100 × 8
P = 800 kg m/s

$\boxed{Force\:Exerted:}$

F = $delta \frac{p}{t}$

F = $\frac{800-500}{6}$

F = $\frac{300}{6}$

F = 50 N $\boxed{Ans}$

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Hope this helps ........ ❤❤☺☺

Answer 2

$\bf{\underline{\underline{Answer:}}}$

$\bf{\therefore 50\:N}$

$\bf{\underline {Given:}}$

Initial velocity, $u \:=\:5\:{s}^{-1}$

Final velocity, $v \:=\:8\:{s}^{-1}$

Mass of the given object, $m = 100\:kg$

Time, $t\:=\:6\:s$

$\bf{\underline {To\:Find:}}$

Initial momentum and final momentum =?

Magnitude of force exerted on the object =?

We know that,

Momentum, p = Mass × Velocity

Therefore, initial momentum,

= Mass × Initial velocity

${100×5=500\:kg \:m\:{s}^{-1}}$

Final momentum,

= Mass × Final velocity

${100×8=800\:kg\:m\:{s}^{-1}}$

$<b>To find the magnitude of the force exerted on the object :</b>$

We know that,

$v \:= \:u \:+ \:at$

$8 \:= \:5 \:+ \:a\:×\:6$

$8 \:-\:5 \:= \:a\:×\:6$

$a =\dfrac{3}{6}\:=\:0.5\:m\:{s}^{-2}$

Now, force exerted on object

= Mass × Accleration

= 109 × 0.5

$= \bf{50\:N}$