Question

An object of mass 100 kg is accelerated uniformly from a velocity of 5 metre per second to 8 metre per second in 6 seconds calculate the initial and final momentum of the object find the magnitude of the force exerted on the object?
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Answer 1

Your answer is given below >>>>>>

Initial velocity of the object, u = 5 m/s

Final velocity of the object, v = 8 m/s

Mass of the object, m = 100 kg

Time take by the object to accelerate, t = 6 s

Initial momentum = mu = 100 — 5 = 500 kg m sˆ’1

Final momentum = mv = 100 — 8 = 800 kg m sˆ’1

Force exerted on the object, F = mv – mu / t

= m (v-u) / t

= 800 – 500

= 300 / 6

= 50 N

Initial momentum of the object is 500 kg m sˆ’1.

Final momentum of the object is 800 kg m sˆ’1.

Force exerted on the object is 50 N.

Answer 2

AnsWer:-

The magnitude of the force exerted on the object is 50 Newton

Step by step explanation:-

Given:-

• Mass of the object = 100 kg
• Initial velocity of the object = 5m/s
• Final velocity of the object = 8m/s
• Time taken by the object = 6 sec

Need to find:-

• Magnitude of the force exerted on the object.

Solution:-

First we have to calculate the initial momentum of the object.

Calculating initial momentum:-

As we know that,

Initial Momentum = mass× initial velocity

=> 100×5

=> 500kg m/s

Now,

Calculating final momentum:-

As we know that,

Final Momentum = mass×final velocity

=> 100×8

=> 800 kg m/s

Now,

As we know that,

force = change in momentum/time taken

Putting values in this formula,

We get:

force = 800-500/6

=> 300/6

=> 50 Newton

Hence,the magnitude of the force exerted on the object is 50 Newton.