Question

An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6 seconds .Calculate the initial and final momentum of the object . Also find the magnitude of the force exerted on that object.

Answer 1

Here is the answer...

Given : u= 5m/s

v= 8m/s

m= 100kg

Pi = mu

Pi = 100x5=500kgm/s

Pf = mv

Pf = 100x8 = 800kgm/s

a = v-u/t

a = 8-5/6= 0.5m/s

F= ma

F= 100x0.5 = 50N

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

u = 5 m/s

v = 8 m/s

m = 100 kg

t = 6 s

Initial momentum = mu = 100 × 5 = 500 kg ms-1 Final momentum = mv= 100 × 8 = 800 kg ms-1

Force exerted on the object,

= (mv−mu)/ t

= 800 - 600 / 6

= 300 / 6

= 50 N

Hence, Force exerted on the object is 50 N.

I hope, this will help you.

Thank you______❤

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