An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms–1 to 8 ms–1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the objec
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Vi =5m/s
Vf = 8m/s
t = 6s
m = 100kg
Initial momentum = m* Vi
= 100*5
= 500kg.m/s
Final momentum = m* Vf
= 100*8
= 800kg.m/s
Now for finding force first find acceleration.
a = (Vf - Vi) / t
= (8 - 5) / 6
= 3/6 = 0.5m/s^2
Force = mass * acceleration
= 100 * 0.5
= 50m/s^2
REGARDS
Vf = 8m/s
t = 6s
m = 100kg
Initial momentum = m* Vi
= 100*5
= 500kg.m/s
Final momentum = m* Vf
= 100*8
= 800kg.m/s
Now for finding force first find acceleration.
a = (Vf - Vi) / t
= (8 - 5) / 6
= 3/6 = 0.5m/s^2
Force = mass * acceleration
= 100 * 0.5
= 50m/s^2
REGARDS
Answered by
0
☺ Hello mate__ ❤
◾◾here is your answer...
u = 5 m/s
v = 8 m/s
m = 100 kg
t = 6 s
Initial momentum = mu = 100 × 5 = 500 kg ms-1 Final momentum = mv= 100 × 8 = 800 kg ms-1
Force exerted on the object,
= (mv−mu)/ t
= 800 - 600 / 6
= 300 / 6
= 50 N
Hence, Force exerted on the object is 50 N.
I hope, this will help you.
Thank you______❤
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