Question

An object of mass 100 kg starts from rest
and attains a velocity of 50 m/s in 10 seconds.
Calculate the acceleration and force applied on
the object​

Answer 1

Answer:

a=5m/s² : F=500 Newton

Explanation:

m=100kg

u=0m/s

v=50m/s

t=10s

a=?

F=?

SOLUTION:v=u+at

50=0+10a

So a=5 m/s²

Now by Newton's 2nd law of motion

F=ma

F=100×5

F=500 Newton

Answer 2

Given :

• Initial velocity (u) = 0 m/s (as it starts from rest)
• Final velocity (v) = 50 m/s
• Time (t) = 10 seconds
• Mass of object (m) = 100 kg

To find :

• Acceleration (a) &
• Force applied (F)

According to the question,

⇢ v = u + at

Where,

• v stands for Final velocity
• u stand for Initial velocity
• t stands for Time
• a stands for Acceleration

⇢ Substituting the values,

⇢ 50 = 0 + a × 10

⇢ 50 - 0 = 10a

⇢ 50 = 10a

⇢ 50 ÷ 10 = a

⇢ 5 = a

.°. The acceleration is 5 m/s².

Now,

⇢ Force = Mass × Acceleration

Or,

⇢ F = ma

⇢ Substituting the values,

⇢ F = 100 × 5

⇢ F = 500 N

So,the force applied is 500 Newton.

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