Question

An object of mass 1000 kg moving at a velocity of 5m/s on a level surface,collides with,and becomes attached to,a stationary object of mass 1500 kg .Calculate the velocity of the two moving objects after collision.

Answer 1

Answer:

2m/s

Explanation:

as per law of conservation of momentum

m1v1+m2v2 =( m1+m2) V

here V IS THE common velocity of body after the inelastic collision

now substitute the values

Answer 2

Answer:

the velocity of the two moving objects after collision is v= 2 m/s

Explanation:

using conservation of momentum

initial momentum = final momentum

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁ = mass of object 1 = 1000 kg

m₂ = mass of object 2 = 1500 kg

u₁ = velocity of object 1 = 5 m/s

u₂ = velocity of object 2 = 0 m/s

v₁ = v₂ = v because both object gets attached together after collision

v(m₁ + m₂) = m₁u₁ + m₂u₂

v = $\frac{m_{1}u_{1} + m_{2}u_{2} }{m_{1} + m_{2} }$

v = $\frac{1000 * 5 + 1500* 0}{1000 + 1500}$

v = $\frac{5000}{2500}$

v= 2 m/s