An object of mass 100g is moving with a constant speed of 50m /s when a force of 5 Newton is applied on it comes into rest calculate the time in which it comes into rest and also calculate the distance travelled by it in during this time interval.
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Explanation:
Retarding force, F=50N
Mass of the body, m=20kg
Initial velocity of the body, u=15m/s
Final velocity of the body, v=0
Using Newtons second law of motion, the acceleration (a) produced is given by:
F=ma
50=20 ×a
a=−50/20=−2.5m/s
2
Using the first equation of motion, the time (t) taken by the body to come at rest
v=u+at
t=−u/a=−15/−2.5=6
Answered by
0
Answer:
Retarding force, F=50N
Mass of the body, m=20kg
Initial velocity of the body, u=15m/s
Final velocity of the body, v=0
Using Newtons second law of motion, the acceleration (a) produced is given by:
F=ma
50=20 ×a
a=−50/20=−2.5m/s
2
Using the first equation of motion, the time (t) taken by the body to come at rest
v=u+at
t=−u/a=−15/−2.5=6s
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