Physics, asked by sagar2kumar987, 1 year ago

An object of mass 100kg is accelerated uniformly from initial velocity of5m/s to 8m/s in 6 second calculate the initial and final momentum of the object also find the magnitude of force exerted on the object?

Answers

Answered by Taaseen
17

Initial momentum = 100 kg x 5 m/s = 500 kg m/s

Final momentum = 100 kg x 8 m/s = 800 kg m/s

Change in momentum = 800 - 500 = 300 kg m/s

Force exerted = change in momentum/time = 300 kg m/s / 6 s = 50 kg m/s2 = 50 N

Answered by pratyush4211
26
Mass Of The Object=100 kg
Changes It Velocity from 5 m/s to 8m/s in 6 seconds.

We know That

\boxed{\mathbf{Momentum=Mass \times Velocity \:kg \:m/s}}

Now.

Intial Velocity =5 m/s

Mass of Object=100 kg

Momentum Now

=5×100

=500 kg m/s

Intial Momentum=500 kg m/s

Now

Final Velocity=8 m/s

Mass of Object=100 kg

Momentum Now

=8×100

=800 kg m/s

Final Momentum=800 kg m/s

Change of Momentum

=Final -Intial Momentum

=800-500

=300 kg m/s

We know That.

Force=Mass×Accerlation.
Force=Mass×(V-u)/time
Force=Mass×Velocity/Time
Force=Momentum/Time

Force =Change in Momentum/Time

=300/6

=50 N

\boxed{\mathbf{\huge{Force=50\:N}}}

Object Have a Certain Mass When A force is Applied on It Move with Certain Velocity . According to its Mass and a certain Force Also Required to bought Object in Rest.It depend on its Mass and Velocity.It is called Momentum.
Similar questions