Question

An object of mass 100kg is accelerated uniformly from a velocity of 5ms-1 to 8ms-1 in 6s . Calculate the initial and final momentum of the object .Also , find the magnitude of the force exerted on the object
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Answer 1

Answer:

500 kg m/s , 800 kg m/s , 50 N.

Explanation:

  We know, momentum = mass * velocity

Object of mass 100 kg has an initial velocity of 5 m/s.  

 So, initial momentum is 100 kg * 5 m/s = 500 kg m/s

the same object accelerates and final velocity becomes 8 m/s.

 So, final momentum is 100 kg * 8 m/s = 800 kg m/s

Acceleration in motion = ( 8 - 5 ) / 6 m/s^2

            = 0.5 m/s^2

Hence, magnitude of force applied is 100 kg * 0.5 m/s^2 = 50 N

Answer 2

GiveN :-

Mass, m = 100 kg

Initial velocity, u = 5 m/s

Final velocity, v = 8 m/s

Time, t = 6 s

TO FinD :-

• The initial and final momentum of the object.

• The magnitude of the force exerted on the object.

AcknowledgemenT :-

• Initial momentum = Mass × Initial velocity

• Final momentum = Mass × Final velocity

SolutioN :-

Initial momentum = 100 × 5

⇒Initial momentum = 500 kg ms⁻¹

$\rule{190}{2}$

Final momentum = 100 × 8

⇒Final momentum = 800 kg ms⁻¹

$\rule{190}{2}$

We know,

$\sf{Acceleration=\dfrac{Final\ velocity-Initial velocity}{Time}}$

$\sf{\implies a=\dfrac{8-5}{6} }\\\\\sf{\implies a=\dfrac{3}{6} }\\\\\sf{\implies a=\dfrac{1}{2} =0.5\ m/s^2}$

We also know,

Force = Mass × Acceleration

⇒F = 100 × 0.5

⇒F = 50 N