Question

An object of mass 10kg changes it's velocity from 15m/s to 20m/s in a time interval of 5 seconds . Calculate the force acted upon this object during that time.​

Answer 1

Explanation:

Given: m= 10 kg, u= 15 m/sec, v= 20m/sec, t= 5 seconds.

F= ?

We know that

F= mv-mu/t

F= m(v-u)/t

F= 10(20-15)/5

F= 10× 5/5

F= 50/5

F= 10 N

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Answer 2

Explanation:

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