Question

An object of mass 10kg is dropped for a height 100 cm find kinectic energy and welocity before as it reaches the ground

Answer 1

mass = 10kg

height = 100cm = 1 m

KE = PE = mgh = 10×9.8×1 = 98 J

KE = 98 J

=> 1/2 mv^2 = 98

=> v^2 = 98×2 / 10

=> v^2 = 19.6

=> v = √19.6 m/s

=> v = 4.4 m/s


Kinetic energy is 98J and velocity is 4.4 m/s

Answer 2

$\huge\bf{Answer:-}$

• 10kg is the mass
• 100cm is the length
• 100cm =>1 m

• KE = PE = MGH = 10×9.8×1 = 98 J

• 98 J => KE

$= \frac{1}{2} mv {}^{2} = 98</p><p>$

$= v {}^{2} = \frac{98 \times 2}{10}$

$= v {}^{2} = 19.6 </p><p>$

$= v = \sqrt{19.6} \: m/s$

$= (v = 4.4 m/s)$

98J and velocity is 4.4 m/s => kinectic energy.