Question

An object of mass 10kg is dropped from a height of 5m above ground. Show that the total energy of the object iat 5m and 2m is same. (g=10m/s^2). what happens to the energy when object touches the ground.

Answer 1

mass =10 kg
h = 5 m
now energy at 5 m =mgh =potential energy
= 10×10×5
=500 Joule
again energy when object at 2 m= k.e

$\frac{1}{2} m \times {v}^{2}$
so 1/2 ×10 ×10^2. (taking g = speed of object)
=500 joule
when object touches the ground energy will be distributed on the ground.i.e the kinetic energy of object.