Question

An object of mass 10kg is kept at rest. A force of 10N is applied on it. Find, Speed of the object at t=5 seconds.​

Answer 1

Answer:

5m/s

Step-by-step explanation:

Force, f = 10N

mass, m = 10 kg

we know that,

f = ma

so, 10 = 10×a

hence, a = 1m/s²

Now,

initial velocity, u = 0m/s

a = 1m/s²

time, t = 5s

Apply, v = u + at

v = 0 + 1×5 = 5m/s

Answer provided by GauthMath.

Answer 2

Given that,

mass (m) = 10 kg

force (F) = 10 N

time (t) = 5s

Since, F = ma and acceleration (a) = Speed/ time

therefore, F = m × Speed/ t

10N = 10kg × Speed/ 5s

2 × Speed = 10 N

Speed = 5 m/s