An object of mass 10kg is kept on a horizontal table.On application of force of 20 N ,the object shifts horizontally by 8 m.If the applied force makes an angle of 60° with the horizontal,find the work done.
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1
20×8cos60°
=20×8×1/2
=80j
=20×8×1/2
=80j
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4
force = 20N
displacement = 8m
angle = 60°
work = FScos60°
= 20 x 8 x 1/2
= 20 x 4
= 80 J
displacement = 8m
angle = 60°
work = FScos60°
= 20 x 8 x 1/2
= 20 x 4
= 80 J
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