An object of mass 10kg is moving with a speed of 5m/s.The object is brought to rest in 0.5 seconds by an external system. The force applied by the external system is.
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Answer:
1N
Explanation:
a = v-u/t
a= 0.5-0/5
a =0.1m/sec2
f= ma
f = 10*0.1
f=1N
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