Question

An object of mass 10kg is moving with a velocity of 20m/s. A force is applied so that in 40seconds, it attains a velocity of 50m/s. What is the force applied on the object?

Answer 1

mass = 10kg

u = 20m/s

t = 40s

v = 50 m/s

v = u + at

a = v - u / t

a = 50 - 20/40

a = 30/40

a =  0.75 m/s^2

therefore;

F = ma

F = 10 x 0.75

F = 7.5 N

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force\:applied=5\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}}$

$\tt: \implies Mass \: of \: object(m) = 10 \: kg$

$\tt: \implies Initial \: velocity(u) = 20 \: m/s$

$\tt: \implies Final \: velocity(v) = 30 \: m/s$

$\tt: \implies Time(t) = 20 \: sec$

$\red{\underline \bold{To \:Find :}}$

$\tt: \implies Force \: applied(F) =?$

• Given Question

$\bold{As \: we \: know \: that}$

$\tt: \implies v = u + at$

$\tt: \implies 30 = 20 + a \times 20$

$\tt: \implies 30 - 20 =20 \times a$

$\tt: \implies a = \frac{10}{20}$

$\green{\tt: \implies a = 0.5 \: ms^{2} }$

$\bold{As \: we \: know \: that}$

$\tt: \implies F= ma$

$\tt: \implies F= 10 \times 0.5$

$\green{\tt: \implies F = 5 \: N}$

$\green{\tt \therefore Force \: applied \: is \: 5 \: N}$