Question

An object of mass 10kg is whirled round in a horizontal circle of radius 4 m by a revolving string that is inclined to vertical. if the uniform speed of the object is 5 m/s..
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Answer 1

Explanation:

144 n

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Answer 2

Answer:

Angle of Inclination= 32° and Tension= 117.91 N

Explanation:

Given:

m= 10kg

r=4m

v=5 m/s

θ=?

T=?

We Know,

Tcosθ= mg - (i)

Tsinθ= mv^2/r - (ii)

Dividing equation (i) and (ii), we get,

tanθ= v^2/rg  

∴ θ= 32°  

Putting the value of θ in equation (i), we get,

T cos32°  = 9.8*10 or, 10*10

∴ T= 117.91 N