An object of mass 10kg moving with a velocity of 5.6ms on a horizontal rough surface comes to rest after 16m then coefficient of friction is
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Mass 10 kg u = 5.6ms v=o coffiecient of friction = ?
R = mg 10*10 = 100
V*v -u*u=2as
0*0 -5.6*5.6 =2*a*32
a= 31.36/32=0.98 m/s
F= ma
10* 0.98 = 9.8N
F = coffiecient of friction / R
9.8 / 100=0.098
R = mg 10*10 = 100
V*v -u*u=2as
0*0 -5.6*5.6 =2*a*32
a= 31.36/32=0.98 m/s
F= ma
10* 0.98 = 9.8N
F = coffiecient of friction / R
9.8 / 100=0.098
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