Question

An object of mass 1kg moving on a horizontal surface
with initial velocity 8 m/s comes to rest after 10 s
calculate the retardation and the retarding force on the body.

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Answer 1

Answer:

Retardation = 0.8 m/s^2 and Retarding Force = 0.8 N

Explanation:

Mass(m) = 1 Kg

Initial Velocity (u) = 8 m/s

Final Velocity (v) = 0m/s [Object stops]

Time = 10 seconds

Now,

Acceleration(a) = v-u

t

= 0-8

10

-8/10 = -0.8 m/s^2

Now, Retardation = 0.8 m/s^2

Thus,

Retarding Force(F) = m×Retardation

= 1×0.8 = 0.8 N