Question

An object of mass 1Kg moving with velocity 10m/s collides and sticks to a stationary wooden block of mass 5kg. find their comman velocity

Answer 1

Answer:

Given,

m=1kg,u1=10ms−1,M=5kgandu2=0ms−1

From conservation of momentum

Initial momentum = final momentum

mu1+Mu2=(m+M)v

1×10+5×0=(1+5)v

10=6v

Hence, velocity of both isv=35ms−1

Total momentum before is 10kgms−1

From momentum conservation, total momentum after is 10kgms−1