An object of mass 1kg thrown vertically upwards ,reaches a maximum height of 6m.find the work done by the force of gravity during the vertical displacement (take g=10ms^-2)
Answers
Answered by
4
check the attachment
Attachments:
Answered by
24
Answer:
Mass of the object = 1kg
value of g = 10m/s
Force = mass × gravitation
= m×g
= 1 × 10
= 10N
Maximum height attend by the object ( Displacement) = 6m
Work done by gravity =
Force × displacement × cos180°
[cos180° Bcoz of when object is moving in one direction and the force is opposing in opposite direction then the angle between force and Displacement is 180°.]
Work done by gravity = 10 × 6 × -1
since, [cos180° = -1]
= - 60 joule
Similar questions