An object of mass 1kg travelling at 10ms^-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5ms^-1. Calculate the magnitude of Change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Class 9
Physics
Answers
Answer:
ANSWER
Mass of ball(m)=200g=0.2kg
Initial velocity of ball(u)=10ms
−1
Final velocity of ball(v)=5ms
−1
Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms
−1
=−3 Ns
Answer:
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Question :- A hockey ball of mass 200g travelling at 10ms −1 is struck by a hockey stick so as to return it along its original path with a velocity at 5ms −1 . Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Answer :- Mass of hockey ball m=200g=0.2Kg
Initial velocity u=10ms −1
Final velocity v=5ms −1
Since the momentum of the ball = Final momentum – initial momentum,
=mv–mu
=m(v–u)
=−0.2(−5–10)
=0.2×−15=−3Kgms −1
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