Question

An Object of mass 1kg travelling in a straight line with a velocity of 10m/s collides with,and sticks to, a stationary woddwn block of mass 5kg then they both move off together in the same straight line calculate the total momentum just before impact and just after impact also,calculate the velocity of the combined object​

Answer 1

Answer:   1.67 m/s

Explanation:

Given :

masses of the two objects:  m1​ = 1 kg ;    m2 ​= 5 kg  and the velocities of that two object:    u1 ​= 10  m/s ;        u2​ = 0

Momentum of the system just before collision, Pi ​= m1 ​u1 ​+ m2 ​u2​

Pi ​= 1 x 10 + 5 x 0 = 10 kg m/s

Mass of the combined object, M = m1​ + m2​ = 6 kg

Let velocity of combined object be v.

According to conservation of momentum,

momentum of the system just after the collision, Pf ​= Pi​

Pf ​ = 10 kg m/s

M v = 10

or, 6 x v = 10        

or, v = 5 / 3 m/s = 1.67 m/s

Answer 2

Answer:

Given,

m = 1kg,

u1=10ms−1

M=5 kg and

u2= 0ms−1

From conservation of momentum

Initial momentum = final momentum

mu1 + Mu2 = (m+M)v

1×10 + 5×0 = (1+5)v

10=6v

Hence, the velocity of both is v =5/3ms−1

Total momentum before is 10 kgms−1

From momentum conservation, total momentum after is 10kgms−1.

Explanation:

Hope it helps