An object of mass 2.5 kg is thrown upwards with a speed of 30 m/s. Calculate its kinetic
energy when it reaches a height of 20 m.
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Answer:
Given, mass of the ball, m=5kg
Speed of the ball, v=10m/s
(a) Initial kinetic energy of the ball,
E
k
=
2
1
mv
2
=
2
1
(5)(10)
2
=250J
When the ball reaches the highest point, its kinetic energy becomes zero and
the entire kinetic energy is converted into its potential energy.
∴E
p
=250J
(b) If h is the maximum height attained by the ball,
E
p
=mgh or mgh=250J
or h=
mg
250
=
(5)(10)
250
=5m
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