An object of mass 2 kg is lifted vertically through a distance of 1.5 m. The work done in process is
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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
Given,
✔ Mass of object = 2 kg.
✔ Height to which it is raised (DISTANCE) = 1.5 m.
✔ We already know from first that, Acceleration due to gravity = 9.8 m/s². We may also consider it as approximately 10 m/s² and thats what we have done in PROCEDURE-2.
❄❄❄❄ SOLUTION ❄❄❄❄
⚡ PROCEDURE 1 :- Work done = Potential energy = mgh (where, "m" is mass, "g" is acceleration due to gravity and "h" is height to which the body is raised.) = (2×1.5×9.8) Joule = 29.4 Joule
⚡ PROCEDURE 2 :- If we consider, "g=10m/s²", then, Work done = mgh = (2×1.5×10) Joule = 30 Joule
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
Given,
✔ Mass of object = 2 kg.
✔ Height to which it is raised (DISTANCE) = 1.5 m.
✔ We already know from first that, Acceleration due to gravity = 9.8 m/s². We may also consider it as approximately 10 m/s² and thats what we have done in PROCEDURE-2.
❄❄❄❄ SOLUTION ❄❄❄❄
⚡ PROCEDURE 1 :- Work done = Potential energy = mgh (where, "m" is mass, "g" is acceleration due to gravity and "h" is height to which the body is raised.) = (2×1.5×9.8) Joule = 29.4 Joule
⚡ PROCEDURE 2 :- If we consider, "g=10m/s²", then, Work done = mgh = (2×1.5×10) Joule = 30 Joule
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
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Answer:
29.4 this is honest to the
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