Question

an object of mass 2 kg is sliding with a velocity of 4 metre per second on a frictional horizontal surface the retarding force necessary to stop the object in one second​

Answer 1

Answer:

-(8-f)N

Explanation:

u=4m/s ; v = 0 ; t=1s ; m = 2kg

v= u+at

0= 4+a*1

a=-4m/s^2

now F+f= ma

F-f = 2 * (-4) = -8N

F = -(8-f)N

f is the friction which is already against the motion